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<c:set var="title" value="1.两数之和"></c:set>
<c:set var="level" value="Easy"></c:set>
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                <p>
                    给定一个整数数组
                    <code>nums</code>
                    &nbsp;和一个整数目标值
                    <code>target</code>
                    ，请你在该数组中找出
                    <strong>和为目标值</strong>
                    <em>
                        <code>target</code>
                    </em>

                    &nbsp; 的那&nbsp;
                    <strong>两个</strong>
                    &nbsp;整数，并返回它们的数组下标。
                </p>

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                <p>你可以假设每种输入只会对应一个答案。但是，数组中同一个元素在答案里不能重复出现。</p>

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                    你可以按任意顺序返回答案。
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        <p>
            <strong>示例 1：</strong>
        </p>

        <pre>
    <strong>输入：</strong>
    nums = [2,7,11,15], target = 9
    <strong>输出：</strong>
    [0,1]
    <strong>解释：</strong>
    因为 nums[0] + nums[1] == 9 ，返回 [0, 1] 。
    </pre>
        <p>
            <strong>示例 1：</strong>
        </p>

        <pre>
    <strong>输入：</strong>
    nums = [2,7,11,15], target = 9
    <strong>输出：</strong>
    [0,1]
    <strong>解释：</strong>
    因为 nums[0] + nums[1] == 9 ，返回 [0, 1] 。
    </pre>

        <p>
            <strong>示例 1：</strong>
        </p>

        <pre>
    <strong>输入：</strong>
    nums = [2,7,11,15], target = 9
    <strong>输出：</strong>
    [0,1]
    <strong>解释：</strong>
    因为 nums[0] + nums[1] == 9 ，返回 [0, 1] 。
    </pre>

        <p>&nbsp;</p>

        <p>
            <strong>提示：</strong>
        </p>

        <ul>
            <li><code>2 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>
            <li><code>-10<sup>9</sup> &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>
            <li><code>-10<sup>9</sup> &lt;= target &lt;= 10<sup>9</sup></code></li>
            <li><strong>只会存在一个有效答案</strong></li>


        </ul>

        <p><strong>进阶：</strong>你可以想出一个时间复杂度小于 <code>O(n<sup>2</sup>)</code> 的算法吗？</p>

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            <span class="css-16xftbw-Type e1oinl1z2">通过次数</span>
            <span class="css-1ne6r7t-Count e1oinl1z3">3,208,810</span>

            <span class="css-16xftbw-Type e1oinl1z2">提交次数</span>
            <span class="css-1ne6r7t-Count e1oinl1z3">6,122,973</span>
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